CLA - Programming Essentials in C Quizzes Chapter 4 Assessment Exam Answers Full 100%

Last Updated on May 20, 2021 by Admin

CLA – Programming Essentials in C Quizzes Chapter 4 Assessment Exam Answers Full 100%

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        int i = 3, j = i - 2; 
        switch(i - 2) { 
        case 1: j++; 
        case 2: j++; 
        case 0: j++; break; 
        default:j = 0; 
        } 
        printf("%d",j); 
        return 0; 
    }

the program outputs 3
the program outputs 2
the program outputs 1
the program outputs 4

What happens if you try to compile and run this program?#include <stdio.h>

    #include <stdio.h> 
    #include <stdio.h> 
    int main(void) { 
        int i = 3, j = i - 2; 

        switch(i + 2) { 
        case 1: j++; 
        case 2: j++; 
        default:j = 0; 
        case 0: j++; break; 
        } 
        printf("%d",j); 
        return 0; 
    }

the program outputs 4
the program outputs 1
the program outputs 3
the program outputs 2

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        int i, t[5]; 

        t[0] = 0; 
        for(i = 1; i < 5; i++) 
        	t[i] = t[i - 1] + i; 
        printf("%d",t[4]); 
        return 0; 
    }

the program outputs 10
the program outputs 9
the program outputs 8
the program outputs 11

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        int i, t[5]; 

        t[4] = 0; 
        for(i = 3; i >= 0; i--) 
        	t[i] = t[4] * i; 
        printf("%d",t[0]); 
        return 0; 
    }

the program outputs 1
the program outputs 2
the program outputs -1
the program outputs 0

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        int t[2]; 
    
        t[0] = 1; t[1] = 0; 
        printf("%d",t[t[t[t[t[0]]]]]); 
        return 0; 
    }

the program outputs -1
the program outputs 0
the program outputs 2
the program outputs 1

What happens if you

try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        int i,t[3]; 
    
        for(i = 2; i >=0 ; i--) 
        	t[i] = i - 1; 
        printf("%d",t[1] - t[t[0] + t[2]]); 
        return 0; 
    }

the program outputs -1
the program outputs 2
the program outputs 1
the program outputs 0

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        int i,t[4] = { 1, 2, 4, 8 }; 

        for(i = 0; i < 2 ; i++) 
        	t[i] = t[3 - i]; 
        printf("%d",t[2]); 
        return 0; 
    }

the program outputs 8
the program outputs 4
the program outputs 2
the program outputs 1

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        int s,i,t[] = { 0, 1, 2, 3, 4, 5 }; 
    
        s = 1; 
        for(i = 2; i < 6 ; i += i + 1) 
        	s += t[i]; 
        printf("%d",s); 
        return 0; 
    }

the program outputs 4
the program outputs 2
the program outputs 8
the program outputs 1

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        char t[] = { 'a', 'b', 'A', 'B' }; 

        printf("%d",t[1] - t[0] + t[3] - t[2]); 
        return 0; 
    }

the program outputs 2
the program outputs 4
the program outputs 1
the program outputs 8

What happens if you try to compile and run this program?
```
    #include <stdio.h> 
    int main(void) { 
        float t[5] = { 1E0, 1E1, 1E2, 1E3, 1E4 }; 
    
        printf("%f",t[0] + t[2] + t[3]); 
        return 0; 
    }
```
- the program outputs 1011.000000
- the program outputs 1111.000000
- the program outputs 1110.000000
- the program outputs 1101.000000
What happens if you try to compile and run this program?
```
    #include <stdio.h> 
    int main(void) { 
        int i = 1, *j = &i, **k = &j; 

        printf("%d",**k); 
        return 0; 
    }
```
- the program outputs 1
- the program outputs NULL
- the program outputs nul
- the program outputs 0

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        char t[3]; 

        printf("%d",sizeof(t) - sizeof(t[0])); 
        return 0; 
    }

the program outputs 4
the program outputs 2
the program outputs 3
the program outputs 1

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        int t[6]; 

        printf("%d",sizeof(t) / sizeof(int)); 
        return 0; 
    }

the program outputs 8
the program outputs 6
the program outputs 4
the program outputs 2

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        int t[10] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }, *p = t + 4; 
    
        p += *p; 
        printf("%d",*p); 
        return 0; 
    }

the program outputs 8
the program outputs 10
the program outputs 7
the program outputs 9

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        int t[10] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }, *p = t; 
    
        p += 2; 
        p += p[-1]; 
        printf("%d",*p); 
        return 0; 
    }

the program outputs 1
the program outputs 5
the program outputs 3
the program outputs 7

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        char s[] = "\0\1\2\3\4"; 

        printf("%c",'A' + s[3]); 
        return 0; 
    }

the program outputs A
the program outputs D
the program outputs B
the program outputs C

What happens if you try to compile and run this program?
```
    #include <stdio.h> 
    int main(void) { 
        printf("%c","ACEGIK"[3] - 1); 
        return 0; 
    }
```
- the program outputs E
- the program outputs F
- the program outputs G
- the program outputs H

What happens if you try to compile and run this program?

    #include <stdio.h> 
    #include <string.h> 
    int main(void) { 
        char s[10] = "ABCDE"; 

        strcpy(s + 2, "ABCDE"); 
        printf("%d", s[0] - s[2]); 
        return 0; 
    }

the program outputs -1
the program outputs 0
the program outputs 1
the program outputs -2

What happens if you try to compile and run this program?

    #include <stdio.h> 
    #include <string.h> 
    int main(void) { 
        char s[10] = "CABDE"; 

        strcat(s + 2, "CABDE"); 
        printf("%d", s[0] - s[2]); 
        return 0; 
    }

the program outputs -1
the program outputs 1
the program outputs -2
the program outputs 0

What happens if you try to compile and run this program?

    #include <stdio.h> 
    #include <string.h> 
    int main(void) { 
        char s[10] = "ABCDE"; 

        strcat(s + 2, "ABCDE"); 
        printf("%d", s[0] - s[2]); 
        return 0; 
    }

the program outputs 1
the program outputs -1
the program outputs 0
the program outputs -2