Last Updated on November 2, 2020 by Admin
A company has a network address of 192.168.1.64 with a subnet mask of 255.255.255.192. The company wants to create two subnetworks that would contain 10 hosts and 18 hosts respectively. Which two networks would achieve that? (Choose two.)
- 192.168.1.16/28
- 192.168.1.64/27
- 192.168.1.128/27
- 192.168.1.96/28
- 192.168.1.192/28
Answers Explanation & Hints: Subnet 192.168.1.64 /27 has 5 bits that are allocated for host addresses and therefore will be able to support 32 addresses, but only 30 valid host IP addresses. Subnet 192.168.1.96/28 has 4 bits for host addresses and will be able to support 16 addresses, but only 14 valid host IP addresses.